Integrand size = 12, antiderivative size = 15 \[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=-x+\frac {\cos (x)}{1-\sin (x)} \]
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Time = 0.07 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {4476, 2814, 2727} \[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=\frac {\cos (x)}{1-\sin (x)}-x \]
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Rule 2727
Rule 2814
Rule 4476
Rubi steps \begin{align*} \text {integral}& = \int \frac {\sin (x)}{1-\sin (x)} \, dx \\ & = -x+\int \frac {1}{1-\sin (x)} \, dx \\ & = -x+\frac {\cos (x)}{1-\sin (x)} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.93 \[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=-x+\frac {2 \sin \left (\frac {x}{2}\right )}{\cos \left (\frac {x}{2}\right )-\sin \left (\frac {x}{2}\right )} \]
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Result contains complex when optimal does not.
Time = 0.24 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.13
method | result | size |
risch | \(-x +\frac {2}{{\mathrm e}^{i x}-i}\) | \(17\) |
default | \(-2 \arctan \left (\tan \left (\frac {x}{2}\right )\right )-\frac {2}{\tan \left (\frac {x}{2}\right )-1}\) | \(19\) |
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none
Time = 0.25 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.87 \[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=-\frac {{\left (x - 1\right )} \cos \left (x\right ) - {\left (x + 1\right )} \sin \left (x\right ) + x - 1}{\cos \left (x\right ) - \sin \left (x\right ) + 1} \]
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\[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=\int \frac {\tan {\left (x \right )}}{- \tan {\left (x \right )} + \sec {\left (x \right )}}\, dx \]
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none
Time = 0.30 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.87 \[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=-\frac {2}{\frac {\sin \left (x\right )}{\cos \left (x\right ) + 1} - 1} - 2 \, \arctan \left (\frac {\sin \left (x\right )}{\cos \left (x\right ) + 1}\right ) \]
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none
Time = 0.29 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.93 \[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=-x - \frac {2}{\tan \left (\frac {1}{2} \, x\right ) - 1} \]
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Time = 22.80 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.93 \[ \int \frac {\tan (x)}{\sec (x)-\tan (x)} \, dx=-x-\frac {2}{\mathrm {tan}\left (\frac {x}{2}\right )-1} \]
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